Don't know where to put this, but...

How about doing a Dollar function vs R function?

Some comparisons i made

n$[1] = aprox. nR0

n$[n] = aprox. nR[1]

n$[[0]] = aprox. nR[0]

n$[[0]1] = aprox nR[0]1

n$[[0][0]] = aprox. nR[0][0]

n$[[1]] = aprox. nR[1]

n$[[n]] = aprox. nR[n]

n$[[[0]]] = aprox. nR[[0]]


So dollar and R catches up at n$[[0]2] and nR[0,1]

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