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Nice to meet you. I'm Anpokan,a Japanese student.

I'm studying BEAF and I found something strange about Multidimensional arrays. http://googology.wikia.com/wiki/Introduction_to_BEAF#Multidimensional_arrays

It says \{a,b (1) 1,2\}=\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{._{._.}}}}.

How many "a" does the array have? I verified.

Let b,p be 3,5.


\begin{align}
\{b,p (1) 1,2\} &= \{3,5 (1) 1,2\} \\
&= \{3,3,3,3,3 (1) \{3,4 (1) 1,2\},1\} \\
&= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3 (1) 1,2\},1\}\} \\
&= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,2 (1) 1,2\},1\}\}\} \\
&= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,3 (1) \{3,1 (1) 1,2\},1\}\}\}\} \\
&= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,3 (1) 3\}\}\}\}  
\end{align}

The first array has five 3's but the 2nd one has four 3's and the 3rd one has three 3's…

when a nth array makes a n+1th array, p is decreased by one so the number of prime block of the n+1th array will decrease and decrease…

I think such a form(\{a,b (1) 1,2\}=\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{._{._.}}}}) will mislead us with the number of a.

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