## FANDOM

10,844 Pages

First, Let me try to express the notation so far in Terms of the FGH.

$Tb = 10^b about f_2$
$aTb$ is similar to tetration $f_3$
aTb@c@d about $f_4$
aTb@..@c with x terms - $f_4$
aTb@@c - $f_5$
? aTb@@c@f - $f_{5}$
aTb@@c@@f - $f_{5}$
aTb@@@f - $f_{6}$
aTb(@^@)c - $f_{\omega }$
aTb(@^^@)c - $f_{\omega^\omega}$

Going even further...

aTb(@^^@)10@5 =
aTb(@^^@)5T10 = >
aTb(@^^5T10)5T10 = >
The height of the power tower of @ is 10^^6

T7(@^^@)10(@^^@)6
First, the 10(@^^@)6 turns into 10(@^^6)6
T7(@^^@)10(@^@^@^@^@^@)6
T7(@^^@)10(@^@^@^@^@^6)6
T7(@^^@)10(@^@^@^@^@^6)6 T7(@^^@)10(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6 Then the last 5 turns into several copies of (@^@^@^@^@^4), which turns into several copies of (@^@^@^@^@^3), (@^@^@^@^@^2), then finally (@^@^@^@^@). Then you have to keep going down the power tower until you get 10@a@b....@z with a GIANT number of @.