## FANDOM

10,828 Pages

This is really salad. Croutonillion gave me this idea.

If you have QSF(n-1), QSF(n) is made like this ( "X" refers to the result of the previous operation.):

0. X=QSF(n-1)

1. X+QSF(0)

2. X+QSF(1)

...

n+1. X+QSF(n-1)

n+2. X+(QSF(0)+QSF(1))

...

(all combination of QSF(a)+QSF(b) is added here)

...

around n^2/2. X+(QSF(n-2)+QSF(n-1))

next. X+(QSF(0)+QSF(1)+QSF(2))

...

(all combination of QSF(a)+QSF(b)+QSF(c) is added here)

...

(all combination of QSF(a)+QSF(b)+QSF(c)+QSF(d) is added here)

...

around 2^n. X+(QSF(0)+QSF(1)+...+QSF(n-1))

Next, do 1-around 2^n again with "X*" instead of "X+."

Next, do 1-around 2^n again, changing all plus into times.

Next, do previous two lines again, with "X^" instead of "X*."

Next, do 1-around 2^n again, changing all plus into exponentiation.

Then...

Repeat what you have done X![QSF(0),QSF(1),...QSF(n-2),QSF(n-1)] times.

Repeat what you have done X![QSF(0),QSF(1),...QSF(n-1),QSF(n-2)] times.

Repeat what you have done X![QSF(0),QSF(1),...QSF(n-2),QSF(n-1),QSF(n-3)] times.

...(Do that for every single permutation for QSF(n) in order.)

Now you get QSF(n).

Do you think are we finished? This is the beginning!

I will define a number below, which is getting longer in each edition.

1. QSF(X)
2. QSF(QSF(X))
3. QSF(QSF(QSF(X)))
4. Keep going on until the number of QSF becomes QSF(0).
5. X^^...^^X (X ^'s)
6. Repeat 1-5 X times
7. Repeat 1-6 X times
8. $QSF^{QSF(X)}(X)$
9. $QSF^{QSF^{QSF(X)}(X)}(X)$
10. Keep going on until the number of QSF becomes QSF(0).
11. $\{X(X)X\}$
12. X^X+X^X^X+...+X^^X

This is the Quite-Salad-Number in the version you're looking at.