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E powers of googol are also done quite easy.

Googol = 1>100

E googol= E 1>100 = 1>100>100 = 1>(1>102)

is then a googol to the power of a googol.


A googolplex = 1>(1>100),so

E googolplex =

1>((1>100)>(1>100))=

1>(1>((1>97)~100)) is

a googolplex to the power of a googolplex.


A googolduoplex =

1>(1>(1>100))

E 1>(1>(1>100)) =

1>(1>((1>((9re97)~8~(9re2)))~(1>100))) is 

a googolduoplex to the power of a googolduoplex.


It's also possible to calculate powers of 10 this way;

I call it the C power (complex extended owb power).


C 1>1 = 10^10^10....10 tens in the power tower....^10^10

C 1>2 = 100^........100 times 100 in the power tower..........


The formula for 

C 1>a can be proven to be 1>(a>(a>a))


So this also is possible for googol,googolplex and googolduoplex and as far as you like.


C googol=

1>(100>(100>100))=

1>(100>(1>102))=

1>(1>((1>101)~2))


C googolplex =

1>((1>100)>((1>100)>(1>100)))=

1>((1>100)> (1>((1>97)~100)) )=

1>(1>((1>((1>98)~97))~100))

This constitutes the number of a

googolplex to the powertower of a googolplex googolplexes.

thus ggp ^ggp ^ ggp......(googolplex terms of googolplex)...^ggp^ggp.



C googolduoplx =

1>((1>(1>100))>((1>(1>100))>(1>(1>100))))=

1>((1>(1>100))>(1> (1>((1>100)-(nl(1>100)))~(1>100))))=

1>((1>(1>100))>((1>(9re97~8~9re2))~(1>100)))=

1>(1>((1>((1>((9re98)>2))~((9re97)~8~(9re2)))~(1>100)))


So to say it in visual terms,

if we take the number of 98 nine's with 2 zero's behind it,so it looks like

99 999 999 99......9999 999 999 900.

This is the amount of zero's behind a 1 so that is the number

1000..........(9re98>2 zero's).........000000000

but behind this last zero come's 97 nine's then an 8 then still 2 nine's,together;

100......(9re98>2zero's).....000 000~999 999 9.....(97nine's)...99 99~8~99

Take this number as the amount of zero's behind a 1.

so thats 

1000.....(1000....(9re98>2 zero's)...000~9re97~8~99)....000 000

and after this follows a 1 with 100 zero's still ,together;

1000....((1000....(((9re98)>2)zero's)...000~999...97nine's...999~8~99)zero's)....000~100....(100zero's)....000

This constitutes the number of zero's behind a 1 again;

100..( [100..( {100..(((9re98)>2)zero's)..00~99..(97nine's)..99~8~99} zero's)..00~100..(100zero's)..00] zero's)...000

Then this last number eventually is the amount of zero's behind a 1 ;

and that is the outcome of

C googolduoplex.

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