## FANDOM

10,818 Pages

This is an extension to this post.

## New Notations

$F_{n}^{b}(X)=F_{n}^{b-1}(F_{n}(X));F_{n}^{0}(X)=X$ (Assumed to be 1 if ommited)

$F_{n}^{b}(X)\#h=F_{n}^{F_{n}^{b}(X)\#h-1}(X);F_{n}^{b}(X)\#1=F_{n}^{b}(X)$ (Assumed to be 1 if ommited)

$F_{n}^{b}(X)\#h\z=F_{n}^{b}(X)\#(F_{n}^{b}(h)\#z-1)\z-1;F_{n}^{b}(X)\#h\1=F_{n}^{b}(X)\#h$

## New Rules

The Grand prefix has been redefined to produce integer values. It is now $F_{n}^{X+1}(X)$. The Superior prefix is unchanged.

The Great prefix now represents $F_{n}(X)\#X$

"Grandsuperior" gives $F_{n}^{X+2}(X)$; and "y-superior" gives $F_{n}^{y+1}(X)$

The "Grandsuperior" and "y-superior" compound prefixes are treated as seperate words, while "Grand" and "Superior" are not.

"Great Grand" gives $F_{n}^{X+1}(X)\#X$; "Great Grandsuperior" gives $F_{n}^{X+2}(X)\#X$; and "Great y-superior" gives $F_{n}^{y+1}(X)\#X$

"y-great" gives $F_{n}(X)\#X^{y}$

"Great" and "y-great" are both treated as seperate words.

The "Omega" prefix yields $F_{n}(X)\#1\X$, and "Omegreat" yields $F_{n}(X)\#X\X$. These are both treated as seperate words.

## Some Numbers

### Grandeuteroex

The redefined Grandeuteroex is $F_{1}^{3}(2)$, or about $2^{2^{2.68\times10^{154}}}$

It is also equal to Bisuperior Deuteroex

### Great Deuteroex

The Great Deuteroex is $F_{1}(2)\#2=F_{1}^{10}(2)=F_{1}(F_{1}(F_{1}(F_{1}(F_{1}(F_{1}(F_{1}(F_{1}(F_{1}(2))))))))))$

It can be expanded to the following:

$2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{2+2^{1+2^{1}}}}}}}}}}}}}}}}}}}}$

### Great Grandeuteroex

$F_{1}^{3}(2)\#2=F_{1}^{F_{1}^{3}(2)}(2)=F_{1}^{Grandeuteroex}(2)$ That means its the grandeuteroexth term in a sequence where the zeroth term is two and each following term is F1 of the previous term.

### Trigreat Decasuperior Googoloex

I have no idea just how big this is, but it's consistent with the naming rules. It is equal to $F_{1}^{11}(10^{100})\#10^{300}$

### Omegreat Grandgoogoloex

Another incredibly large one. This one is equal to $F_{1}^{10^{100}+1}(10^{100})\#10^{100}\10^{100}$